At topmost position, v = 0 ⇒ momentum = 0
The momentum of an object is given by the product of its mass and velocity. At the maximum height, the velocity becomes zero (momentarily), and if the mass remains constant, the momentum will indeed become zero at that point.
Therefore, in the context of the object thrown vertically upwards, the correct option is (A): Momentum.
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Knowing the initial position \( x_0 \) and initial momentum \( p_0 \) is enough to determine the position and momentum at any time \( t \) for a simple harmonic motion with a given angular frequency \( \omega \).
Reason (R): The amplitude and phase can be expressed in terms of \( x_0 \) and \( p_0 \).
In the light of the above statements, choose the correct answer from the options given below:
Which of the following graph shows the variation of velocity with mass for the constant momentum?
A body initially at rest undergoes rectilinear motion. The force-time (F-t) graph for the motion of the body is given below. Find the linear momentum gained by the body in 2 s.
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.