Question

An ideal gas goes from an initial state to final state. During the process, the pressure of the gas increases linearly with temperature.
A. The work done by gas during the process is zero.
B. The heat added to the gas is different from the change in its internal energy.
C. The volume of the gas is increased.
D. The internal energy of the gas is increased.
E. The process is isochoric (constant volume process).
Choose the correct answer from the options given below:

• A. A, B, C, D Only
• B. A, D, E Only
• C. E Only
• D. A, C Only

Hint:

In processes involving ideal gases, when the volume remains constant, the work done is zero. The heat added in such a case is equal to the change in internal energy. This type of process is called an isochoric process.

Answer 1

The Correct Option is B

We are given that the pressure of the gas increases linearly with temperature. The relationship between pressure and temperature for an ideal gas is given by: \[ P = aT + b, \] where \( a \) and \( b \) are constants. This suggests a linear increase in pressure with temperature.
- Option A: The work done by gas during the process is zero. In the case of a process where the pressure increases linearly with temperature, the volume must remain constant. This would result in no work done by the gas since \( W = P \Delta V \), and \( \Delta V = 0 \). 
Thus, Option A is correct.
- Option B: The heat added to the gas is different from the change in its internal energy. 
For an ideal gas undergoing any process, the heat added is related to both the work done and the change in internal energy. In this case, since there is no change in volume, the heat added is used to increase the internal energy of the gas. 
Thus, Option B is incorrect because the heat added will be equal to the change in internal energy for an isochoric process.
- Option C: The volume of the gas is increased. 
As we established earlier, since this is an isochoric process (constant volume), the volume of the gas does not change. Option C is incorrect.
- Option D: The internal energy of the gas is increased. 
In an ideal gas, the internal energy depends only on the temperature. Since the temperature increases in this process, the internal energy of the gas increases. Thus, Option D is correct.
- Option E: The process is isochoric (constant volume process). 
Given that no work is done by the gas, and the pressure increases with temperature, this suggests that the volume remains constant. Hence, Option E is correct.
Thus, the correct answer is \( \boxed{A, D, E { Only}} \).