Step 1: The potential energy of a dipole in an electric field is given by: \[ U = -pE \cos\theta \] where:
- \( p \) is the dipole moment, - \( E \) is the electric field,
- \( \theta \) is the angle between the dipole moment and the electric field.
Step 2: The change in potential energy when the dipole is rotated by 45° is: \[ \Delta U = U(\theta = 45^\circ) - U(\theta = 0^\circ) \] Substituting \( \theta = 45^\circ \) and \( \theta = 0^\circ \): \[ \Delta U = -pE \cos 45^\circ + pE \cos 0^\circ = -pE \left(\frac{1}{\sqrt{2}}\right) + pE = pE \left(1 - \frac{1}{\sqrt{2}}\right) \]
Step 3: Simplifying: \[ \Delta U = pE \left(\frac{\sqrt{2} - 1}{\sqrt{2}}\right) \]
Thus, the energy required to rotate the dipole by 45° is \( pE \left(\frac{\sqrt{2} - 1}{\sqrt{2}}\right) \).
Consider a positively charged infinite cylinder with uniform volume charge density \(\rho>0\). An electric dipole consisting of +Q and -Q charges attached to opposite ends of a massless rod is oriented as shown in the figure. At the instant as shown in the figure, the dipole will experience,