Question

Inside a closed surface, n electric dipoles are situated. The electric flux coming out from the closed surface will be

• A. \( \frac{q}{\epsilon_0} \)
• B. \( \frac{2q}{\epsilon_0} \)
• C. \( \frac{nq}{\epsilon_0} \)
• D. zero

Hint:

In Gauss's law, if the enclosed charge is zero (as in the case of dipoles), the electric flux is also zero.

Answer 1

The Correct Option is D

Step 1: Concept of electric flux.
Electric flux through a closed surface is given by Gauss's law: \[ \Phi_E = \frac{q_{\text{enc}}}{\epsilon_0} \] where: - \( q_{\text{enc}} \) is the charge enclosed by the surface, - \( \epsilon_0 \) is the permittivity of free space. Step 2: Electric flux from dipoles.
For an arrangement of electric dipoles, the net charge enclosed inside a closed surface is zero because the dipoles have equal and opposite charges that cancel each other out.
Step 3: Conclusion.
Thus, the electric flux coming out from the closed surface will be zero.
\[ \boxed{0} \]