Question

The distance between two equal and opposite charges of \( 0.2 \mu C \) will be 3.0 cm. Their electric dipole moment will be

• A. \( 6.0 \times 10^{-8} \) coulomb-metre
• B. \( 6.0 \) coulomb-metre
• C. \( 12.0 \times 10^{-8} \) coulomb-metre
• D. \( 12.0 \) coulomb-metre

Hint:

Electric dipole moment = charge \(\times\) separation distance. Always convert units properly, like microcoulombs to coulombs and cm to meters.

Answer 1

The Correct Option is A

Step 1: Formula for electric dipole moment.
The electric dipole moment (\( p \)) is given by the formula: \[ p = q \times d \] where: - \( q \) is the charge - \( d \) is the separation distance between the charges. Step 2: Given values.
Given: - \( q = 0.2 \, \mu C = 0.2 \times 10^{-6} \, C \) - \( d = 3.0 \, \text{cm} = 0.03 \, \text{m} \) Substitute the values into the formula: \[ p = (0.2 \times 10^{-6} \, C) \times (0.03 \, \text{m}) = 6.0 \times 10^{-8} \, \text{C m} \] Step 3: Conclusion.
Thus, the electric dipole moment is \( 6.0 \times 10^{-8} \, \text{C m} \).
\[ \boxed{6.0 \times 10^{-8} \, \text{C m}} \]