The electric flux $\Phi_E$ is given by:
\[ \Phi_E = E \times A \] where $E = 3 \times 10^3 \, \text{N/C}$ and $A = 10 \times 30 = 300 \, \text{m}^2$.
Thus, the flux is: \[ \Phi_E = 3 \times 10^3 \times 300 = 9 \times 10^3 \, \text{Vm} \]
Two charges of \(5Q\) and \(-2Q\) are situated at the points \((3a, 0)\) and \((-5a, 0)\) respectively. The electric flux through a sphere of radius \(4a\) having its center at the origin is: