A player caught a cricket ball of mass 150 g moving at a speed of 20 m/s. If the catching process is completed in 0.1 s, the magnitude of force exerted by the ball on the hand of the player is:
- 150 N
- 3 N
- 30 N
- 300 N
The Correct Option is C
Solution and Explanation
The force exerted is:
\[ F = \frac{\Delta P}{\Delta t}. \]
Here:
\[ \Delta P = m \cdot v - 0 = 150 \times 10^{-3} \cdot 20 \, \text{kg m/s}, \]
\[ F = \frac{150 \times 10^{-3} \cdot 20}{0.1}. \]
\[ F = 30 \, \text{N}. \]
Final Answer: 30 N.
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