Question

A gas expands from volume \(V\) to \(2V\) at constant pressure \(P\). What is the work done by the gas?

• A. \(PV\)
• B. \(2PV\)
• C. \(\frac{PV}{2}\)
• D. Zero

Hint:

In an isobaric process, the area under the \(P\)-\(V\) graph (a rectangle) gives the work: \(W = P \Delta V\).

Answer 1

The Correct Option is A

Step 1: Use the formula for work done at constant pressure (isobaric process) Work done by a gas during isobaric expansion: \[ W = P(V_2 - V_1) \] Given: - \(V_1 = V\) - \(V_2 = 2V\) - \(P = P\) (constant) \[ W = P(2V - V) = P \cdot V \] Step 2: Final Answer The work done by the gas is \(PV\). Answer: Hence, the correct answer is option (1) \(PV\).