To find the percentage error in the physical quantity \( Q \) given by the relation \(Q = \frac{a^4 b^3}{c^2}\), we use the formula for percentage error in a derived quantity:
Let's analyze each of the terms individually:
Therefore, the total percentage error in \( Q \) is:
| Percentage error in \( Q \) | = \( 12\% + 12\% + 10\% \) |
| = \( 12\% + 12\% + 10\% = 34\% \) |
Hence, the percentage error in \( Q \) is \(34\%.\)
Therefore, the correct answer is 34%.
Given: \(Q = \frac{a^4 b^3}{c^2}\)
The percentage error in \( Q \) can be calculated using the rule for propagation of errors in multiplication and division.
Step 1. Calculate the fractional error in \( Q \):
\(\frac{\Delta Q}{Q} = 4 \frac{\Delta a}{a} + 3 \frac{\Delta b}{b} + 2 \frac{\Delta c}{c}\)
Step 2. Substitute the given percentage errors:
\(\frac{\Delta Q}{Q} \times 100 = 4 \left( \frac{\Delta a}{a} \times 100 \right) + 3 \left( \frac{\Delta b}{b} \times 100 \right) + 2 \left( \frac{\Delta c}{c} \times 100 \right)\)
\(= 4 \times 3\% + 3 \times 4\% + 2 \times 5\%\)
\(= 12\% + 12\% + 10\%\)
Step 3. Calculate the total percentage error in \( Q \):
\(\text{Percentage error in } Q = 12\% + 12\% + 10\% = 34\%\)
Thus, the percentage error in \( Q \) is 34%.
The Correct Answer is: 34%
Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?

Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.