1. Calculate Total Mass of Reactants (\(m_r\)):
\[ m_r = 235.0439 \, \text{u}. \]
2. Calculate Total Mass of Products (\(m_p\)):
\[ m_p = 139.9054 + 93.9063 + 1.0086 = 234.8203 \, \text{u}. \]
3. Calculate Disintegration Energy (\(Q\)):
The disintegration energy \(Q\) is given by:
\[ Q = (m_r - m_p)c^2. \]
Substitute the values:
\[ Q = (235.0439 - 234.8203) \times 931. \]
Simplify:
\[ Q = 0.2236 \times 931 = 208.1716 \, \text{MeV}. \]
Answer: \(208 \, \text{MeV}\)
Let \[ I(x) = \int \frac{dx}{(x-11)^{\frac{11}{13}} (x+15)^{\frac{15}{13}}} \] If \[ I(37) - I(24) = \frac{1}{4} \left( b^{\frac{1}{13}} - c^{\frac{1}{13}} \right) \] where \( b, c \in \mathbb{N} \), then \[ 3(b + c) \] is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).