Step 1: Understanding the Formula for Speed of Light in a Medium
The speed of light in any medium is given by the formula:
\[
v = \frac{c}{n}
\]
where:
- \(v\) is the speed of light in the medium
- \(c\) is the speed of light in vacuum (which is \(3 \times 10^8\) m/s)
- \(n\) is the refractive index of the medium
Step 2: Applying the Formula
Given that the refractive index of glass is \(n = 1.5\), and the speed of light in air is \(c = 3 \times 10^8\) m/s, we can calculate the speed of light in glass as:
\[
v = \frac{3 \times 10^8}{1.5} = 2 \times 10^8 \, \text{m/s}
\]
Step 3: Conclusion
Thus, the speed of light in glass is \(2 \times 10^8\) m/s. The correct answer is option (B).
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = 4/3 \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \frac{n_2}{2n_1} \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is cm. 
$PQ$ is a chord of length $4\ \text{cm}$ of a circle of radius $2.5\ \text{cm}$. The tangents at $P$ and $Q$ intersect at a point $T$. Find the length of $TP$.
Find the unknown frequency if 24 is the median of the following frequency distribution:
\[\begin{array}{|c|c|c|c|c|c|} \hline \text{Class-interval} & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 \\ \hline \text{Frequency} & 5 & 25 & 25 & \text{$p$} & 7 \\ \hline \end{array}\]