To solve the problem of determining the temperature needed to double the pressure of a gas within a fixed volume, we apply the Ideal Gas Law in the form of Charles's law, which is given by:
\( \frac{P_1}{T_1} = \frac{P_2}{T_2} \)
Here, \(P_1\) is the initial pressure, \(T_1\) is the initial temperature in Kelvin, \(P_2\) is the final pressure, and \(T_2\) is the final temperature in Kelvin.
The initial condition is at 27°C, which is 300K (since \(T(K) = T(°C) + 273\)). We aim to double the pressure (\(P_2 = 2P_1\)).
Solving for \(T_2\):
\[ \frac{P_1}{300} = \frac{2P_1}{T_2} \]
By simplifying, we find:
\[ T_2 = 2 \times 300 = 600 \, \text{K} \]
Convert back to Celsius: \(T(°C) = T(K) - 273\):
\(T_2 = 600 - 273 = 327°C\).
Thus, the temperature should be raised to 327°C to double the pressure.
The motion of an airplane is represented by the velocity-time graph as shown below. The distance covered by the airplane in the first 30.5 seconds is km.
The least acidic compound, among the following is
Choose the correct set of reagents for the following conversion: