Initially :
\(\frac{1}{4}\)=1−\(\frac{300}{T_H}\)
⇒ TH = 400 K
Finally, : Efficiency becomes \(\frac{1}{2}\)
∴\(\frac{1}{2}\)=1−\(\frac{300}{T_H}\)
∴TH=600 K
⇒ The temperature of the source increases by 200°C.
The correct option is (B) : Increases by 200°C.
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
From the second law of thermodynamics, two important results are derived where the conclusions are taken together to constitute Carnot’s theorem. It may be stated in the following forms.