Let the initial position of the bird be \( A \), and the position after 2 seconds be \( B \). The height of the tree is \( 80 \, \text{m} \), and the angle of elevation from point \( P \) to the bird at \( A \) is \( 45^\circ \).
Step 1: Calculate the horizontal distance at position \( A \)
Using the tangent function for \( \angle 45^\circ \), we can write:
\[
\tan(45^\circ) = \frac{80}{x_1},
\]
where \( x_1 \) is the horizontal distance from point \( P \) to the tree at the initial position. Since \( \tan(45^\circ) = 1 \), we have:
\[
1 = \frac{80}{x_1} \quad \Rightarrow \quad x_1 = 80 \, \text{m}.
\]
Step 2: Calculate the horizontal distance at position \( B \)
After 2 seconds, the angle of elevation becomes \( 30^\circ \). Using the tangent function for \( \angle 30^\circ \), we have:
\[
\tan(30^\circ) = \frac{80}{x_2},
\]
where \( x_2 \) is the new horizontal distance. Since \( \tan(30^\circ) = \frac{1}{\sqrt{3}} \), we get:
\[
\frac{1}{\sqrt{3}} = \frac{80}{x_2} \quad \Rightarrow \quad x_2 = 80\sqrt{3} \approx 80 \times 1.732 = 138.56 \, \text{m}.
\]
Step 3: Calculate the distance traveled by the bird
The bird travels from \( x_1 = 80 \, \text{m} \) to \( x_2 = 138.56 \, \text{m} \). The distance traveled is:
\[
\text{Distance traveled} = x_2 - x_1 = 138.56 - 80 = 58.56 \, \text{m}.
\]
Step 4: Calculate the speed of the bird
The bird travels this distance in 2 seconds, so the speed \( v \) is:
\[
v = \frac{\text{Distance}}{\text{Time}} = \frac{58.56}{2} = 29.28 \, \text{m/s}.
\]
Conclusion:
The speed of the flying bird is \( 29.28 \, \text{m/s} \).