\( \frac{13}{66} \)
Total balls = \( 3 + 4 + 5 = 12 \). Total ways to draw 2 balls = \( \binom{12}{2} = 66 \).
Same color:
- Red: \( \binom{3}{2} = 3 \)
- White: \( \binom{4}{2} = 6 \)
- Blue: \( \binom{5}{2} = 10 \)
Total favorable = \( 3 + 6 + 10 = 19 \).
Probability = \( \frac{19}{66} \).
Thus, the answer is \( \frac{19}{66} \).
When $10^{100}$ is divided by 7, the remainder is ?