Question:

A coin is tossed three times. The probability of getting at least two heads is:

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To find the probability of at least two heads, calculate the sum of probabilities for exactly two and three heads using the binomial formula, or use the complement rule.
  • \(\frac{1}{2}\)
  • \(\frac{3}{8}\)
  • \(\frac{1}{8}\)
  • \(\frac{1}{4}\)
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The Correct Option is A

Solution and Explanation

When a coin is tossed three times, the total number of possible outcomes is \(2^3 = 8\) (HHH, HHT, HTH, THH, HTT, THT, TTH, TTT). The favorable outcomes for getting at least two heads are those with exactly two heads or three heads: - Exactly two heads: HHT, HTH, THH (3 outcomes) - Three heads: HHH (1 outcome) Total favorable outcomes = \(3 + 1 = 4\). The probability is the number of favorable outcomes divided by the total number of outcomes: \[ \text{Probability} = \frac{4}{8} = \frac{1}{2} \]
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