Question

A coin is tossed three times. The probability of getting at least two heads is:

• A. \(\frac{1}{2}\)
• B. \(\frac{3}{8}\)
• C. \(\frac{1}{8}\)
• D. \(\frac{1}{4}\)

Hint:

To find the probability of at least two heads, calculate the sum of probabilities for exactly two and three heads using the binomial formula, or use the complement rule.

Answer 1

The Correct Option is A

When a coin is tossed three times, the total number of possible outcomes is \(2^3 = 8\) (HHH, HHT, HTH, THH, HTT, THT, TTH, TTT). The favorable outcomes for getting at least two heads are those with exactly two heads or three heads: - Exactly two heads: HHT, HTH, THH (3 outcomes) - Three heads: HHH (1 outcome) Total favorable outcomes = \(3 + 1 = 4\). The probability is the number of favorable outcomes divided by the total number of outcomes: \[ \text{Probability} = \frac{4}{8} = \frac{1}{2} \]