Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed.
Based on the above information, answer the following
Given:
Assumption: The appointments are independent, i.e., both persons may be appointed.
\[ P(W) = P(A) \cdot P(W|A) + P(B) \cdot P(W|B) \]
\[ P(W) = (0.5)(0.7) + (0.6)(0.4) = 0.35 + 0.24 = 0.59 \]
\[ \boxed{P(W) = 0.59} \]
Given:
\[ P(A|W) = \frac{P(A) \cdot P(W|A)}{P(W)} \]
\[ P(A|W) = \frac{0.5 \cdot 0.7}{0.59} = \frac{0.35}{0.59} \]
\[ P(A|W) = \frac{35}{59} \approx 0.5932 \]
\[ \boxed{P(A|W) \approx 0.5932} \]
Three distinct numbers are selected randomly from the set \( \{1, 2, 3, \dots, 40\} \). If the probability, that the selected numbers are in an increasing G.P. is \( \frac{m}{n} \), where \( \gcd(m, n) = 1 \), then \( m + n \) is equal to:
A board has 16 squares as shown in the figure. Out of these 16 squares, two squares are chosen at random. The probability that they have no side in common is:
For the curve \( \sqrt{x} + \sqrt{y} = 1 \), find the value of \( \frac{dy}{dx} \) at the point \( \left(\frac{1}{9}, \frac{1}{9}\right) \).
Find the Derivative \( \frac{dy}{dx} \)
Given:\[ y = \cos(x^2) + \cos(2x) + \cos^2(x^2) + \cos(x^x) \]