Comprehension

Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed. 
Based on the above information, answer the following 

Question: 1

What is the probability that the waste treatment plant is introduced?

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Solution and Explanation

Given:

  • Let \( A \): First person is appointed, \( P(A) = 0.5 \)
  • Let \( B \): Second person is appointed, \( P(B) = 0.6 \)
  • Let \( W \): Waste treatment plant is introduced
  • \( P(W|A) = 0.7 \), \( P(W|B) = 0.4 \)

Assumption: The appointments are independent, i.e., both persons may be appointed.

Step 1: Apply Total Probability Theorem

\[ P(W) = P(A) \cdot P(W|A) + P(B) \cdot P(W|B) \]

Step 2: Substitute Given Values

\[ P(W) = (0.5)(0.7) + (0.6)(0.4) = 0.35 + 0.24 = 0.59 \]

✅ Final Answer:

\[ \boxed{P(W) = 0.59} \]

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Question: 2

After the selection, if the waste treatment plant is introduced, what is the probability that the first person had introduced it?

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Solution and Explanation

Given:

  • \( P(A) = 0.5 \), \( P(W|A) = 0.7 \)
  • \( P(W) = 0.59 \) (from Total Probability Theorem)

Step 1: Apply Bayes’ Theorem

\[ P(A|W) = \frac{P(A) \cdot P(W|A)}{P(W)} \]

Step 2: Substitute Values

\[ P(A|W) = \frac{0.5 \cdot 0.7}{0.59} = \frac{0.35}{0.59} \]

Step 3: Simplify

\[ P(A|W) = \frac{35}{59} \approx 0.5932 \]

✅ Final Answer:

\[ \boxed{P(A|W) \approx 0.5932} \]

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