Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed.
Based on the above information, answer the following
Given:
Assumption: The appointments are independent, i.e., both persons may be appointed.
\[ P(W) = P(A) \cdot P(W|A) + P(B) \cdot P(W|B) \]
\[ P(W) = (0.5)(0.7) + (0.6)(0.4) = 0.35 + 0.24 = 0.59 \]
\[ \boxed{P(W) = 0.59} \]
Given:
\[ P(A|W) = \frac{P(A) \cdot P(W|A)}{P(W)} \]
\[ P(A|W) = \frac{0.5 \cdot 0.7}{0.59} = \frac{0.35}{0.59} \]
\[ P(A|W) = \frac{35}{59} \approx 0.5932 \]
\[ \boxed{P(A|W) \approx 0.5932} \]
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
Find the Derivative \( \frac{dy}{dx} \)
Given:\[ y = \cos(x^2) + \cos(2x) + \cos^2(x^2) + \cos(x^x) \]