Question

A 10 L vessel contains 1 mole of an ideal gas with pressure of P(atm) and temperature of T(K). The vessel is divided into two equal parts. The pressure (in atm) and temperature (in K) in each part is respectively.

• A. \( \frac{P}{2} \), \( \frac{T}{2} \)
• B. \( P \), \( T \)
• C. \( \frac{P}{2} \), \( T \)
• D. \( P \), \( \frac{T}{2} \)

Hint:

Remember, when the volume of an ideal gas is divided, the temperature and pressure might remain the same in each section, depending on the context.

Answer 1

The Correct Option is B

In the given problem, we are asked to find the pressure and temperature in each part of the vessel when it is divided into two equal parts. The temperature remains unchanged as the ideal gas follows Boyle's law (constant temperature). Therefore, the pressure will also remain unchanged because the volume is halved while the number of moles remains constant. Hence, both pressure and temperature in each part will be the same.