We need to find the numerically greatest term in the expansion of \( (5 + 3x)^6 \). The general term in the binomial expansion of \( (5 + 3x)^6 \) is: \( T_r = \binom{6}{r} 5^{6-r} (3x)^r \)
Step 1: Substitute \( x = 1 \) into the general term: \( T_r = \binom{6}{r} 5^{6-r} 3^r \)
Step 2: The term will be greatest when the powers of 3 and 5 are balanced. After solving, the greatest term occurs when \( r = 3 \), and the value is \( 3^3 \times 5^5 \).
If
$ 2^m 3^n 5^k, \text{ where } m, n, k \in \mathbb{N}, \text{ then } m + n + k \text{ is equal to:} $
Let $ (1 + x + x^2)^{10} = a_0 + a_1 x + a_2 x^2 + ... + a_{20} x^{20} $. If $ (a_1 + a_3 + a_5 + ... + a_{19}) - 11a_2 = 121k $, then k is equal to _______