The reaction is as follows:
\[\text{C}_6\text{H}_5\text{NH}_2 + \text{NaNO}_2 + \text{HCl} \xrightarrow{T<5^\circ \text{C}} \text{C}_6\text{H}_5\text{-N}_2^+\text{Cl}^-\xrightarrow{\text{Phenol}} \text{Orange Dye}\]
1 mole of aniline (C$_6$H$_5$NH$_2$) produces 1 mole of orange dye.
Molar mass of aniline = 93 g mol$^{-1}$.
Molar mass of orange dye = 199 g mol$^{-1}$.
Moles of aniline used:
\[\text{moles of aniline} = \frac{\text{mass of aniline}}{\text{molar mass of aniline}} = \frac{9.3}{93} = 0.1 \, \text{mol}.\]
Mass of orange dye produced:
\[\text{mass of orange dye} = \text{moles of aniline} \times \text{molar mass of orange dye} = 0.1 \times 199 = 19.9 \, \text{g} \approx 20 \,\text{g}.\]
The best reagent for converting propanamide into propanamine is:
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32