
In this reaction, a hydroxymethyl group (\(-{CH2OH}\)) reacts with thionyl chloride (\({SOCl2}\)) to form the corresponding chloro derivative.
The product is benzyl chloride, and the reaction proceeds via the conversion of the hydroxyl group into a good leaving group, followed by substitution with chlorine.
Product structure:
\[ {C6H5CH2Cl} \]
Quick Tip:
Thionyl chloride (\({SOCl2}\)) is widely used to convert alcohols into alkyl chlorides with high efficiency.
In this reaction, styrene (\({C6H5CH=CH2}\)) reacts with \({HBr}\) in the presence of a peroxide.
Due to the peroxide effect (Kharasch effect), the reaction follows a free radical mechanism, giving the anti-Markovnikov product. This means that the bromine atom attaches to the less substituted carbon of the double bond.
Major Product: 1-bromo-2-phenylethane
\[ {C6H5CH2CH2Br} \]
This reaction is a classic example of free radical addition to alkenes influenced by the presence of peroxides.
Identify A in the following reaction. 
For the reaction, \(N_{2}O_{4} \rightleftharpoons 2NO_{2}\) graph is plotted as shown below. Identify correct statements.
A. Standard free energy change for the reaction is 5.40 kJ \(mol^{-1}\).
B. As \(\Delta G\) in graph is positive, \(N_{2}O_{4}\) will not dissociate into \(NO_{2}\) at all.
C. Reverse reaction will go to completion.
D. When 1 mole of \(N_{2}O_{4}\) changes into equilibrium mixture, value of \(\Delta G = -0.84 \text{ kJ mol}^{-1}\).
E. When 2 mole of \(NO_{2}\) changes into equilibrium mixture, \(\Delta G\) for equilibrium mixture is \(-6.24 \text{ kJ mol}^{-1}\).
Choose the correct answer from the following.
