The combustion of methane is represented by the equation: \[ \text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(l) \] Given: $\Delta H_{\text{CH}_4} = -75 \, \text{kJ/mol}$
$\Delta H_{\text{CO}_2} = -393.5 \, \text{kJ/mol}$
$\Delta H_{\text{H}_2\text{O}} = -285.8 \, \text{kJ/mol}$
What is the enthalpy change ($\Delta H$) for the combustion of 1 mole of methane?