Question:
Which of the following statements is not correct for glucose?
Which of the following statements is not correct for glucose?
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Pentaacetate of glucose can still react with reagents like \( \mathrm{NH_2OH} \), indicating the presence of a carbonyl group.
Updated On: Jun 6, 2025
- Glucose does not give Schiff's test.
- Glucose exists in two crystalline forms \(\alpha\)- and \(\beta\)-.
- The pentaacetate of glucose does not react with \( \mathrm{NH_2OH} \).
- Glucose forms addition product with \( \mathrm{NaHSO_3} \).
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The Correct Option is C
Solution and Explanation
Step 1: Glucose contains an aldehyde group in its open-chain form and can react with hydroxylamine (\( \mathrm{NH_2OH} \)) to form an oxime.
Step 2: The pentaacetate of glucose does not have a free –CHO group, but it still retains the carbonyl nature and can react with hydroxylamine.
Step 3: Hence, the statement that pentaacetate of glucose does not react with \( \mathrm{NH_2OH} \) is incorrect.
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