Step 1: The transformation from I to II involves the coupling of an aryl halide with an alkyl halide in the presence of sodium, which is characteristic of the Wurtz-Fittig reaction.
Step 2: The transformation from I to III involves acylation of the aromatic ring with an acyl halide in the presence of AlCl\(_3\), which is a Friedel-Crafts acylation reaction.
Step 3: Therefore, the reactions A and B are Wurtz-Fittig and Friedel-Crafts respectively.