Step 1: The product Y is an alkene (C\(_5\)H\(_{10}\)), formed by dehydration of an alcohol X (C\(_5\)H\(_{12}\)O) in the presence of copper at high temperature.
Step 2: To form alcohol X, a ketone like propanone reacts with a Grignard reagent like ethyl magnesium bromide.
Step 3: This reaction yields a secondary alcohol, which on heating with Cu/573K eliminates water to give the corresponding alkene.