Question

$XY$ is the membrane / partition between two chambers 1 and 2 containing sugar solutions of concentration $\mathrm{c}_{1}$ and $\mathrm{c}_{2}\left(\mathrm{c}_{1}>\mathrm{c}_{2}\right) \mathrm{mol} \mathrm{L}^{-1}$. For the reverse osmosis to take place identify the correct condition} (Here $\mathrm{p}_{1}$ and $\mathrm{p}_{2}$ are pressures applied on chamber 1 and 2 )

• A. Membrane/Partition ; Cellophane, $\mathrm{p}_{1}>\pi$
• B. Membrane/Partition ; Porous. $\mathrm{p}_{2}>\pi$
• C. Membrane/Partition ; Parchment paper, $\mathrm{p}_{1}>\pi$
• D. Membrane/Partition : Cellophane, $\mathrm{p}_{2}>\pi$ Choose the correct answer from the options given below:

Hint:

Reverse osmosis requires the pressure in the chamber with higher concentration to be greater than the osmotic pressure.

Answer 1

The Correct Option is C

1. Normal osmosis occurs from chamber 2 to chamber 1. 
2. For reverse osmosis from chamber 1 to chamber 2, the pressure $\mathrm{p}_{1}$ must be greater than the osmotic pressure $\pi$. 
3. Therefore, the correct conditions are A and C. 
Therefore, the correct answer is (3) A and C only.