Step 1: Structure of C_6H_6
The given compound is C_6H_6, which is benzene. The structure of benzene consists of six carbon atoms arranged in a hexagonal ring, with alternating single and double bonds between them. Each carbon atom is bonded to one hydrogen atom.
Step 2: Valency of Carbon
Carbon has an atomic number of 6, and its electron configuration is 1s\(^2\) 2s\(^2\) 2p\(^2\). Carbon needs four electrons to complete its octet, which gives it a valency of 4. This allows each carbon atom in the benzene ring to form four bonds—one with a hydrogen atom and three with other carbon atoms.
Step 3: Conclusion
Thus, the valency of carbon (C) in C\(_6\)H\(_6\) (benzene) is 4.
\[
\boxed{4}
\]
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
A hydrocarbon which does not belong to the same homologous series of carbon compounds is
Draw a memory drawing of any one of the following by pencil. The drawing should not be less than 15 cm:
\begin{enumerate}[(i)] \item Two Guavas with leaves \item Brinjal \item Two Tomatoes \end{enumerate} Keep in view the following points in drawing: \begin{enumerate}[(i)] \item Beauty of lines \hfill 06 marks \item Resemblance of figures \hfill 04 marks \end{enumerate}
Draw a memory drawing of any one of the following by pencil. The drawing should not be less than 15 cm:
\begin{enumerate}[(i)] \item Copy and pen \item Kite \item Open book \end{enumerate} Keep in view the following points in drawing: \begin{enumerate}[(i)] \item Beauty of lines \hfill 06 marks \item Resemblance of figures \hfill 04 marks \end{enumerate}