If the derivative $f'(x) < 0$ for all values in a domain, then the function is decreasing throughout that domain.
To analyze whether the function is increasing or decreasing, we calculate the derivative of $f(x)$. Given: \[ f(x) = \frac{2}{x} - 5 \] Differentiate $f(x)$ with respect to $x$: \[ f'(x) = \frac{d}{dx}\left(\frac{2}{x}\right) - \frac{d}{dx}(5) = -\frac{2}{x^2} - 0 = -\frac{2}{x^2} \] Now observe the sign of $f'(x)$: - For all $x \ne 0$, $x^2 > 0$ ⟹ $\frac{2}{x^2} > 0$ ⟹ $-\frac{2}{x^2} < 0$ So, $f'(x) < 0$ for all $x \ne 0$. This implies the function is decreasing for all $x \ne 0$.
If the domain of the function \( f(x) = \dfrac{1}{\sqrt{10 + 3x - x^2}} + \dfrac{1}{\sqrt{x + |x|}} \) is \( (a, b) \), then \((1 + a)^2 + b^2\) is equal to: