Question

Which of the following statement(s) is/are correct?

• A. Solid I₂ is freely soluble in water.
• B. Solid I₂ is freely soluble in water but only in the presence of excess KI.
• C. Solid I₂ is freely soluble in CCl₄.
• D. Solid I₂ is freely soluble in hot water.

Answer 1

The Correct Option is B, C

• Statement 1: False. Solid I₂ is only slightly soluble in water.
• Statement 2: True. I₂ dissolves more in water in the presence of KI due to the formation of I⁻₃ complexes.
• Statement 3: True. I₂ is freely soluble in non-polar solvents like CCl₄.
• Statement 4: False. I₂ is not freely soluble in hot water.

Answer 2

Explanation:

• Option 1: Iodine (I₂) is nonpolar, and water (H₂O) is polar. Nonpolar substances do not readily dissolve in polar solvents.
• Option 2: Iodine reacts with potassium iodide (KI) to form the triiodide ion (I₃^-), which is soluble in water, thus increasing iodine's solubility.
• Option 3: Carbon tetrachloride (CCl₄) is nonpolar, and iodine (I₂) is also nonpolar, so they dissolve well in each other.
• Option 4: While solubility increases with temperature, I₂ is not "freely" soluble in hot water compared to solutions with KI.