Question:

Which of the following statement is incorrect?

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In \( \beta \)-elimination reactions (E2), the most stable alkene is generally the major product.
Updated On: Mar 6, 2025
  • \( (-) \)-2-bromooctane reacts with NaOH gives (+)-octan-2-ol by \( {S}_{N}2 \) reaction.
  • 2-Bromobutane reacts with NaOH gives racemic mixture by \( {S}_{N}1 \) reaction.
  • \( \beta \)-elimination of 2-bromopentane gives pent-1-ene as major product.
  • The hybridization of the carbon in the intermediate formed in \( {S}_{N}1 \) reaction is sp\(^2\).
  • Primary alkyl halide undergoes \( {S}_{N}2 \) faster than secondary alkyl halide.
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The Correct Option is C

Solution and Explanation

The \( \beta \)-elimination of 2-bromopentane results in the formation of pent-2-ene as the major product, not pent-1-ene. This is because the most favorable elimination (E2) reaction occurs at the beta position with the most accessible hydrogen. 
Thus, the correct answer is (C).

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