Statement I is incorrect. Propene reacts with diborane (B2H6) to form trialkyl borane, (CH3)2CH-B, which is then oxidized using hydrogen peroxide in the presence of NaOH to produce propan-2-ol. The formula given in Statement I is not the correct addition product. The actual addition product is a trialkyl borane which is formed in the first step.
Statement II is correct. Oxidation of the trialkyl borane by H2O2 in NaOH gives propan-2-ol. This is the hydroboration-oxidation reaction.
List-I | List-II | ||
(A) | [Co(NH3)5(NO2)]Cl2 | (I) | Solvate isomerism |
(B) | [Co(NH3)5(SO4)]Br | (II) | Linkage isomerism |
(C) | [Co(NH3)6] [Cr(CN)6] | (III) | Ionization isomerism |
(D) | [Co(H2O)6]Cl3 | (IV) | Coordination isomerism |