Statement I is incorrect. Propene reacts with diborane (B2H6) to form trialkyl borane, (CH3)2CH-B, which is then oxidized using hydrogen peroxide in the presence of NaOH to produce propan-2-ol. The formula given in Statement I is not the correct addition product. The actual addition product is a trialkyl borane which is formed in the first step.
Statement II is correct. Oxidation of the trialkyl borane by H2O2 in NaOH gives propan-2-ol. This is the hydroboration-oxidation reaction.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :