Question:
Given below are two statements:
Statement I: Propene on treatment with diborane gives an addition product with the formula \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\).
Statement II: Oxidation of \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\) with hydrogen peroxide in presence of NaOH gives propan-2-ol.
In the light of the above statements, choose the most appropriate answer from the options given below:
Given below are two statements:
Statement I: Propene on treatment with diborane gives an addition product with the formula \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\).
Statement II: Oxidation of \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\) with hydrogen peroxide in presence of NaOH gives propan-2-ol.
In the light of the above statements, choose the most appropriate answer from the options given below:
Statement I: Propene on treatment with diborane gives an addition product with the formula \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\).
Statement II: Oxidation of \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\) with hydrogen peroxide in presence of NaOH gives propan-2-ol.
In the light of the above statements, choose the most appropriate answer from the options given below:
Updated On: Jan 13, 2026
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
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The Correct Option is B
Solution and Explanation
Statement I is incorrect. Propene reacts with diborane (B2H6) to form trialkyl borane, (CH3)2CH-B, which is then oxidized using hydrogen peroxide in the presence of NaOH to produce propan-2-ol. The formula given in Statement I is not the correct addition product. The actual addition product is a trialkyl borane which is formed in the first step.
Statement II is correct. Oxidation of the trialkyl borane by H2O2 in NaOH gives propan-2-ol. This is the hydroboration-oxidation reaction.
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