Question:

Which of the following is the correct order of acidic character of oxides of vanadium?

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In general, the acidity of oxides increases as the oxidation state of the metal increases. Higher oxidation states result in stronger acidity.
Updated On: Apr 8, 2025
  • \( \text{V}_2\text{O}_5>\text{VO}_2>\text{V}_2\text{O}_3 \)
  • \( \text{V}_2\text{O}_3>\text{VO}_2>\text{V}_2\text{O}_5 \)
  • \( \text{V}_2\text{O}_5>\text{V}_2\text{O}_3>\text{VO}_3 \)
  • \( \text{VO}_2>\text{V}_2\text{O}_3>\text{V}_2\text{O}_5 \)
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The Correct Option is A

Solution and Explanation


To determine the correct order of acidic character of vanadium oxides, we need to consider the oxidation states of vanadium in each oxide. The acidic nature of oxides increases with the oxidation state of the metal. Oxides in higher oxidation states tend to be more acidic because they can better accept electrons and form acidic solutions in water. - \(\text{V}_2\text{O}_5\): In this oxide, vanadium is in the +5 oxidation state, which makes it highly acidic. - \(\text{VO}_2\): In this oxide, vanadium is in the +4 oxidation state, which makes it moderately acidic. - \(\text{V}_2\text{O}_3\): In this oxide, vanadium is in the +3 oxidation state, which makes it less acidic. Thus, the correct order of acidic character is: \[ \text{V}_2\text{O}_5>\text{VO}_2>\text{V}_2\text{O}_3 \]
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