Question:
Which of the following is soluble in yellow ammonium sulphide?
Which of the following is soluble in yellow ammonium sulphide?
Updated On: Jun 2, 2023
- CuS
- CdS
- SnS
- PbS
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The sulfides of $As ^{3+}, As ^{5+}, Sb ^{3+}, Sb ^{5+}, Sn ^{2+}, Sn ^{4+}$ are soluble in yellow ammonium sulfide where they form polysulphide complexes.
Was this answer helpful?
1
0
Top Questions on Ammonia
- Ammonia is synthesized in the Haber process in the following reaction.
$𝑁_2 (𝑔) + 3𝐻_2 (𝑔) → 2𝑁𝐻_3(𝑔)$
The temperature above which the reaction becomes spontaneous is __________ 𝐾 (rounded off to one decimal place).
($\bigtriangleup 𝐻^0 = −92.2 𝑘𝐽, \bigtriangleup 𝑆^0 = −199 𝐽𝐾^{ −1}$ ) - A gas ‘X’ is added to Nessler’s reagent then brown precipitate is formed, gas X is
- The dehydrating agent for ammonia used in laboratory is
- According to MO theory, number of species/ions from the following having identical bond order is ___.
CN-, NO+, O2, O+2, O2+2 - Reaction of [Co(H2O)6]2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t2g-orbitals of the product is _______
View More Questions
Questions Asked in BITSAT exam
- Let \( ABC \) be a triangle and \( \vec{a}, \vec{b}, \vec{c} \) be the position vectors of \( A, B, C \) respectively. Let \( D \) divide \( BC \) in the ratio \( 3:1 \) internally and \( E \) divide \( AD \) in the ratio \( 4:1 \) internally. Let \( BE \) meet \( AC \) in \( F \). If \( E \) divides \( BF \) in the ratio \( 3:2 \) internally then the position vector of \( F \) is:
- BITSAT - 2024
- Vectors
- Let \( \mathbf{a} = \hat{i} - \hat{k}, \mathbf{b} = x\hat{i} + \hat{j} + (1 - x)\hat{k}, \mathbf{c} = y\hat{i} + x\hat{j} + (1 + x - y)\hat{k} \). Then, \( [\mathbf{a} \, \mathbf{b} \, \mathbf{c}] \) depends on:}
- BITSAT - 2024
- Vectors
- Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L : \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines \( PN \) and \( PQ \), then \( \cos \alpha \) is equal to:
- The magnitude of projection of the line joining \( (3,4,5) \) and \( (4,6,3) \) on the line joining \( (-1,2,4) \) and \( (1,0,5) \) is:
- BITSAT - 2024
- Vectors
- The angle between the lines whose direction cosines are given by the equations \( 3l + m + 5n = 0 \) and \( 6m - 2n + 5l = 0 \) is:
- BITSAT - 2024
- Vectors
View More Questions