We are given that the sum of the first 30 terms of an arithmetic progression (AP) is 930, and the first term is 2. We need to find the common difference \( d \). The formula for the sum of the first \( n \) terms of an arithmetic progression is: \[ S_n = \frac{n}{2} \left[ 2a + (n-1) \cdot d \right] \] where: - \( S_n \) is the sum of the first \( n \) terms, - \( a \) is the first term, - \( d \) is the common difference, - \( n \) is the number of terms. Substituting the known values: \[ S_{30} = \frac{30}{2} \left[ 2(2) + (30-1) \cdot d \right] \] \[ 930 = 15 \left[ 4 + 29d \right] \] \[ 930 = 15(4 + 29d) \] \[ 930 = 60 + 435d \] \[ 930 - 60 = 435d \] \[ 870 = 435d \] \[ d = \frac{870}{435} \] \[ d = 2 \] Thus, the common difference is \( d = 2 \).