Question

Which of the following conversions indicate the presence of –CH\(_2\)OH group in glucose?

• A. Glucose \(\rightarrow\) Gluconic acid
• B. Glucose \(\rightarrow\) n-Hexane
• C. Glucose \(\rightarrow\) Saccharic acid
• D. Glucose \(\rightarrow\) Glucose penta acetate

Hint:

The conversion of glucose to glucose penta acetate involves the esterification of the –OH group, which directly shows the presence of the –CH\(_2\)OH group in glucose.

Answer 1

The Correct Option is D

- The –CH\(_2\)OH group is present in glucose as it is an alcohol group. When glucose undergoes conversion to glucose penta acetate, the –OH group of glucose reacts with acetic acid to form acetates, indicating the presence of the –CH\(_2\)OH group in glucose.
- Gluconic acid is formed when glucose is oxidized, where the aldehyde group is oxidized to a carboxylic acid, and it doesn't indicate the presence of the –CH\(_2\)OH group.

- n-Hexane is not directly related to glucose and indicates a complete conversion to a hydrocarbon, so it doesn't reflect the presence of the alcohol group.
- Saccharic acid is formed when glucose is oxidized at both the aldehyde and alcohol groups, but it doesn't specifically indicate the –CH\(_2\)OH group.
Thus, the correct answer is (4) Glucose \(\rightarrow\) Glucose penta acetate.