In nucleophilic addition reactions, the reactivity of aldehydes and ketones is affected by the electron-withdrawing or electron-donating effects of substituents attached to the aromatic ring or carbonyl group.
The general trend in reactivity is as follows:
- Electron-withdrawing groups (such as \( -NO_2 \)) attached to the aromatic ring increase the electrophilicity of the carbonyl carbon, thus increasing reactivity towards nucleophiles.
- Electron-donating groups (such as \( -CH_3 \)) decrease the electrophilicity of the carbonyl carbon, decreasing reactivity towards nucleophiles.
Now, let's examine the options:
1. \( \text{Benzaldehyde} \): No electron-donating or electron-withdrawing groups are attached to the benzene ring. It has moderate reactivity.
2. \( \text{Acetophenone} \): The \( -CH_3 \) group is an electron-donating group, decreasing the electrophilicity of the carbonyl carbon, so its reactivity is lower than that of benzaldehyde.
3. \( \text{p-Tolualdehyde} \): The \( -CH_3 \) group (electron-donating) attached to the benzene ring lowers the electrophilicity of the carbonyl group, but less than acetophenone. It is more reactive than acetophenone.
4. \( \text{p-Nitrobenzaldehyde} \): The \( -NO_2 \) group (electron-withdrawing) significantly increases the electrophilicity of the carbonyl carbon, making it highly reactive in nucleophilic addition reactions.
Thus, the reactivity order is: \[ \text{Acetophenone} < \text{p-Tolualdehyde} < \text{Benzaldehyde} < \text{p-Nitrobenzaldehyde} \] Final Answer: The correct answer is (3).
The product (A) formed in the following reaction sequence is:
\([A]\) (mol/L) | \(t_{1/2}\) (min) |
---|---|
0.100 | 200 |
0.025 | 100 |