Let the original deposit be \( P \).
Step 1: The annual interest at 5% on the original deposit is: \[ \text{Interest at 5\%} = \frac{5}{100} \times P = 0.05P \]
Step 2: The new annual interest at 6\% on the new deposit \( P + 1000 \) is: \[ \text{Interest at 6\%} = \frac{6}{100} \times (P + 1000) = 0.06(P + 1000) \]
Step 3: The difference in interest is Rs. 110, so: \[ 0.06(P + 1000) - 0.05P = 110 \]
Step 4: Solve for \( P \): \[ 0.06P + 60 - 0.05P = 110 \] \[ 0.01P = 50 \implies P = 5000 \] Thus, the original deposit is Rs. 5,000.