Anil's Investment: Principal = Rs 22000 Rate of interest = 4 percent per annum compounded half-yearly = 2 percent per half-year Time = 6 years = 12 half-years The formula for the amount is:
Amount = Principal × $(1 + \frac{Rate}{100})^{Time}$
Substituting the given values:
Amount = 22000 × $(1 + \frac{2}{100})^{12}$ ≈ 27816.22
Sunil's Investment: Let the initial investment be P. After 5 years at 4 percent compounded half-yearly, the amount becomes:
This amount is then reinvested for 1 year at 10 percent simple interest. So, the final amount for Sunil = \(P \left( 1 + \frac{2}{100} \right)^{10} \left( 1 + \frac{10}{100} \right)\)
Given that both amounts are equal: \(27816.22 = P \left( 1 + \frac{2}{100} \right)^{10} \left( 1 + \frac{10}{100} \right)\)
Solving for P, we get $P \approx 20808$
Therefore, Sunil's initial investment was approximately Rs 20808.