To solve the problem, we need to determine the number of years it will take for a sum of money to become five times itself under simple interest, given that it triples in 8 years.
- Simple Interest (SI): Interest calculated on the original principal for the entire time period.
- Formula: \( \text{SI} = \frac{P \times R \times T}{100} \)
- Final Amount (A): Given by \( A = P + \text{SI} \)
- If a sum triples, it becomes \( 3P \), meaning the interest earned is \( 2P \).
- \( A = 3P \) in 8 years → SI = \( 2P \)
- Using SI formula: \( 2P = \frac{P \times R \times 8}{100} \)
\[ 2P = \frac{P \times R \times 8}{100} \Rightarrow 2 = \frac{R \times 8}{100} \Rightarrow R = \frac{200}{8} = 25\% \]
To become five times, SI = \( 5P - P = 4P \)
Using SI formula:
\[
4P = \frac{P \times 25 \times T}{100}
\Rightarrow 4 = \frac{25T}{100}
\Rightarrow T = \frac{4 \times 100}{25} = 16 \text{ years}
\]
The sum will become five times itself in 16 years.