Question:

When $\psi_A$ and $\psi_B$ are the wave functions of atomic orbitals, then $\sigma^*$ is represented by :

Updated On: Nov 23, 2024
  • $\psi_A - 2\psi_B$
  • $\psi_A - \psi_B$
  • $\psi_A + 2\psi_B$
  • $\psi_A + \psi_B$
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The Correct Option is B

Solution and Explanation

The bonding ($\sigma$) and anti-bonding ($\sigma^*$) molecular orbitals are formed by the constructive and destructive interference of atomic orbitals' wave functions.
For an anti-bonding molecular orbital ($\sigma^*$):
\[ \psi_{\sigma^*} = \psi_A - \psi_B. \]
This occurs due to the out-of-phase overlap of the wave functions, leading to a node between the nuclei and a higher energy state.
Thus, $\sigma^*$ is represented by:
\[ \psi_A - \psi_B. \]

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