Question:

When a polaroid sheet is rotated between two crossed polaroids then the transmitted light intensity will be maximum for a rotation of :

Updated On: Nov 16, 2024
  • \(60^\circ\)
  • \(30^\circ\)
  • \(90^\circ\)
  • \(45^\circ\)
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The Correct Option is D

Solution and Explanation

Let \( I_0 \) be the intensity of unpolarized light incident on the first polaroid.

- The transmitted light intensity after passing through the first polaroid is:

\(I_1 = \frac{I_0}{2}.\)

- The intensity after passing through the second polaroid at an angle \( \theta \) is:

\(I_2 = I_1 \cos^2 \theta = \frac{I_0}{2} \cos^2 \theta.\)

- Similarly, for the third polaroid rotated by \( 90^\circ - \theta \), the transmitted intensity is:

\(I_3 = I_2 \cos^2 (90^\circ - \theta) = \frac{I_0}{2} \cos^2 \theta \sin^2 \theta.\)

- The intensity will be maximum when \( \sin 2\theta = 1 \), which occurs at \( \theta = 45^\circ \).

The Correct answer is: \(45^\circ\)

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