Question:

When a $p-n$ junction diode is reverse biased, then

Updated On: Jul 5, 2022
  • no current flows
  • the depletion region is increased
  • the depletion region is reduced
  • the height of the potential barrier is reduced
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The Correct Option is B

Solution and Explanation

In reverse biasing, the applied voltage $V$ on the $n$-side is positive and is negative on the $p$-side. The applied bias $V$ and the barrier potential $V _{ B }$ are in the same direction making the effective junction potential $V + V _{ B }$. As a result, the junction width will increase. The higher junction potential would restrict the flow of majority carriers to a much greater extent. However, such a field will favour the
flow of minority carriers. So, reverse bias current will be due to the minority carriers only.
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Concepts Used:

Semiconductors

Semiconductors are a crystalline solid materials, whose electrical conductivity lies between a conductor and an insulator. Semiconductors are mainly used in the manufacturing of electronic devices like capacitors, transistors, diodes, Integrated circuits, etc.

Properties of Semiconductor:

  1. Semiconductor acts like an insulator at Zero Kelvin. On increasing the temperature, it works as a conductor.
  2. Due to their exceptional electrical properties, semiconductors can be modified by doping to make semiconductor devices suitable for energy conversion, switches, and amplifiers.
  3. Lesser power losses.

Uses of Semiconductor:

  1. Semiconductors are widely used in manufacturing electronics devices like transistors, diodes, sensors, integrated circuits.
  2. Semiconductors are widely used in all electronic devices, like mobile phones, digital cameras, communication devices, trains, ATMs, etc.