In a p-n junction diode, the behavior between the p and n ends can be understood by analyzing its resistance characteristics. When the resistance is high, the diode is in its "off" state, functioning as an open circuit or a switch that is not conducting.
In the context of this question, the resistance measurement indicates whether or not current can flow through the diode. A high resistance implies that the diode blocks current flow, akin to an open switch, while low resistance means it allows current, acting like a closed switch.
Thus, when the resistance is high, the p-n junction diode effectively acts as a switch in its "off" position, preventing current from passing through.
Therefore, the correct answer to the question is that the diode acts as a switch when the resistance between the p and n ends is high.
Assertion (A): We cannot form a p-n junction diode by taking a slab of a p-type semiconductor and physically joining it to another slab of an n-type semiconductor.
Reason (R): In a p-type semiconductor, \( n_e \gg n_h \) while in an n-type semiconductor \( n_h \gg n_e \).
The graph shows the variation of current with voltage for a p-n junction diode. Estimate the dynamic resistance of the diode at \( V = -0.6 \) V.
