Question

When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of $CO_2$ was produced. The molar mass of compound is _______ $gmol^{−1}$. (Nearest integer).

Answer 1

Correct Answer: 200

- Mass of carbon in the compound: \[ 0.01 \times \frac{60}{100} = 0.006 \, \text{g} \] - Moles of CO\(_2\) produced: \[ \frac{4.4}{44} = 0.1 \, \text{mol} \] - Mass of carbon in CO\(_2\): \[ 0.1 \times 12 = 1.2 \, \text{g} \] - The molar mass \(M\) of the compound: \[ M = \frac{\text{mass of compound}}{\text{moles of compound}} = \frac{0.01}{0.006} \times 12 = 200 \, \text{g/mol} \]