The correct answer is 40
Mass of organic compound = 0.25 g
Mass of AgCl = 0.40 g
%\(Cl=\frac{35.5×mass\ of AgCl}{143.5×(mass\ of\ organic\ compound)}×100\)
\(=\frac{35.5×0.40×100}{143.5×0.25 }\)
= 39.581 ≃ 40%
Therefore , Cl = 40 %
List-I (Name of the test) | List-II (Reaction sequence involved) [M is metal] | |
---|---|---|
(A) Borax bead test | I | |
(B) Charcoal cavity test | II | |
(C) Cobalt nitrate test | III | |
(D) Flame test | IV |