For a head on elastic collision
\(v_2=\frac{mv_1}{m+5m}+\frac{mv_1}{m+5m}\)
=\(\frac{2v_1}{6}\) or \(\frac{v_1}{3}\)
Initial kinetic energy of first mass
=\(\frac{1}{2}mv_1^2\)
Final kinetic energy of second mass
=\(\frac{1}{2}×5m\bigg(\frac{v_1}{3}\bigg)^2\)
=\(\frac{5}{9}\bigg(\frac{1}{2mv_1^2}\bigg)\)
\(⇒\) kinetic energy transferred = \(55\%\) of initial kinetic energy of first colliding mass
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is:
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.