What percentage of kinetic energy of a moving particle is transferred to a stationary particle when it strikes the stationary particle of 5 times its mass? (Assume the collision to be head-on elastic collision)
- 50.0%
- 66.6%
- 55.6%
- 33.3%
The Correct Option is C
Solution and Explanation
For a head on elastic collision
\(v_2=\frac{mv_1}{m+5m}+\frac{mv_1}{m+5m}\)
=\(\frac{2v_1}{6}\) or \(\frac{v_1}{3}\)
Initial kinetic energy of first mass
=\(\frac{1}{2}mv_1^2\)
Final kinetic energy of second mass
=\(\frac{1}{2}×5m\bigg(\frac{v_1}{3}\bigg)^2\)
=\(\frac{5}{9}\bigg(\frac{1}{2mv_1^2}\bigg)\)
\(⇒\) kinetic energy transferred = \(55\%\) of initial kinetic energy of first colliding mass
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Concepts Used:
Kinetic energy
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.
