To solve the problem, we need to understand the kinetic energy of a body moving in a circular path at constant speed.
- Kinetic energy (KE) depends on the mass and speed of the body.
- Formula:
\[
KE = \frac{1}{2} m v^2
\]
where \( m \) is mass and \( v \) is speed.
- When a body moves in a circle at constant speed, its velocity direction changes, but the speed (magnitude of velocity) remains constant.
- Since kinetic energy depends only on speed (not direction), KE remains constant during circular motion.
- Even though the body accelerates towards the center (centripetal acceleration), this does not change its speed.
- Therefore, kinetic energy stays the same as long as speed is constant.
The kinetic energy of a body moving in a circular path with constant speed remains constant.
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is:
Match List I with List II:
Choose the correct answer from the options given below: