What is Y in the following reaction sequence?
1. Reaction of anisole with CH\(_3\)Cl in presence of anhydrous AlCl\(_3\):
This is a Friedel-Crafts alkylation reaction.
The methoxy group (-OCH\(_3\)) is an ortho-para directing group.
The major product (X) will be para-methylanisole (4-methylanisole).
2. Oxidation of 4-methylanisole with KMnO\(_4\)/OH\(^{-}\) followed by H\(_3\)O\(^{+}\):
KMnO\(_4\) in basic medium followed by acidification is a strong oxidizing agent.
It will oxidize the alkyl group attached to the benzene ring to a carboxylic acid group (-COOH).
The methoxy group (-OCH\(_3\)) will remain unaffected.
Y will be 4-methoxybenzoic acid (para-methoxybenzoic acid).
Therefore, Y is 4-methoxybenzoic acid.
List-I | List-II | ||
(A) | NH3 | (I) | Trigonal Pyramidal |
(B) | BrF5 | (II) | Square Planar |
(C) | XeF4 | (III) | Octahedral |
(D) | SF6 | (IV) | Square Pyramidal |
(1) \( x_1 = y_1 \)
(2) \( \frac{x_1 + x_2}{2} = \frac{y_1 + y_2}{2} \)
(3) \( x_2 = y_2 \)
(4) \( (x_1 - x_2)^2 = (y_1 - y_2)^2 \)