Step 1: The reaction starts with the bromobenzene reacting with Mg in ether to form the Grignard reagent (phenylmagnesium bromide).
Step 2: Carbon dioxide is then introduced, which reacts with the Grignard reagent to form benzoic acid upon acidic workup.
Step 3: The benzoic acid undergoes a Hoffmann bromamide reaction, where the amide is converted to an amine, resulting in the formation of aniline.
Thus, the final product formed is aniline (structure in option (1)).
Identify Z in the following reaction sequence.
List-I | List-II | ||
(A) | NH3 | (I) | Trigonal Pyramidal |
(B) | BrF5 | (II) | Square Planar |
(C) | XeF4 | (III) | Octahedral |
(D) | SF6 | (IV) | Square Pyramidal |
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: