Step 1: Write the Reaction
The neutralization reaction between NaOH and HCl is:
$$ \text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + H_2O $$
Step 2: Calculate the Moles of NaOH
Given:
Moles of NaOH:
$$ \text{Moles of NaOH} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{1}{40} = 0.025 \text{ mol} $$
Step 3: Calculate the Moles of HCl
Given:
Moles of HCl:
$$ \text{Moles of HCl} = M \times V = 0.75 \times 0.025 = 0.01875 \text{ mol} $$
Step 4: Determine the Limiting Reagent
The reaction follows a 1:1 molar ratio between NaOH and HCl.
Since HCl has fewer moles, it is the limiting reagent.
Step 5: Calculate Unreacted NaOH
Unreacted moles of NaOH:
$$ \text{Unreacted NaOH} = 0.025 - 0.01875 = 0.00625 \text{ mol} $$
Mass of unreacted NaOH:
$$ \text{Mass} = 0.00625 \times 40 = 0.25 \text{ g} = 250 \text{ mg} $$
Step 6: Conclusion
The mass of unreacted NaOH is 250 mg.
Identify Z in the following reaction sequence.
List-I | List-II | ||
(A) | NH3 | (I) | Trigonal Pyramidal |
(B) | BrF5 | (II) | Square Planar |
(C) | XeF4 | (III) | Octahedral |
(D) | SF6 | (IV) | Square Pyramidal |